Let \(X\) be a Tychonoff space and \(C{(X)}\), \(C{(X,{\mathbb{C}})}\) be the rings of all real-valued and complex-valued continuous functions defined on \(X\) respectively. For each intermediate subring \(A{(X)}\) of \(C{(X)}\), Acharyya and De have introduced the notion of \(z_{A}^{\beta}\)-ideals in \(A{(X)}\) and \(z_{A}^{\beta}\)-filters on \(\beta X\). For each \(A{(X)}\), we extend this notion to \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals and \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filters for an intermediate subring \({\lbrack{A{(X)}}\rbrack}_{c}\) of \(C{(X,{\mathbb{C}})}\), where \({\lbrack{A{(X)}}\rbrack}_{c} = {\{{f + {ig}}:{{f,g} \in {A{(X)}}}\}}\). We establish a correspondence between the collection of \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals in the subrings \({\lbrack{A{(X)}}\rbrack}_{c}\) of \(C{(X,{\mathbb{C}})}\) and the collection of \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filters on \(\beta X\). We study the properties of the \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals. We also deduce that the structure space of the subrings \({\lbrack{A{(X)}}\rbrack}_{c}\) is homeomorphic to \(\beta X\).
Throughout this paper, we take \(X\)
to be a Tychonoff space. Let \(C{(X,{\mathbb{C}})}\), \(C^{\ast}{(X,{\mathbb{C}})}\) denote the
rings of all complex-valued and bounded complex-valued continuous
functions defined on \(X\)
respectively, while \(C{(X)}\), \(C^{\ast}{(X)}\) denote the rings of all
real-valued and bounded real-valued continuous functions defined on
\(X\) respectively. An intermediate
ring of complex-valued continuous functions is a subring of \(C{(X,{\mathbb{C}})}\) which contains \(C^{\ast}{(X,{\mathbb{C}})}\) and we denote
the collection of all these subrings by \(\sum{(X,{\mathbb{C}})}\). Similarly, an
intermediate ring of real-valued continuous functions is a subring of
\(C{(X)}\) which contains \(C^{\ast}{(X)}\) and we denote the
collection of all these subrings by \(\sum{(X)}\). Let \(\beta X\) denote the Stone-Δech
compactificaton of \(X\). In this
paper, we consider an ideal to be a proper ideal.
An elegant bridge between a topological space \(X\) and the algebraic properties of its
associated ring \(C{(X)}\) is the
correspondence between the ideals in \(C{(X)}\) and the \(z\)-filters on \(X\) which is well documented by Gillman and
Jerison in [5]. Mason [6] introduced the concept of \(z\)-ideals to study the ideal structure of
the ring \(C{(X)}\). There is a
bijective correspondence between the \(z\)-ideals in \(C{(X)}\) and \(z\)-filters on \(X\). Redlin and Watson [11] extended the correspondence
between ideals and \(z\)-filters to
intermediate rings \(A{(X)}\) of
real-valued continuous functions by defining \(\mathcal{Z}_{A}{(f)}\) = \(\{ E \in Z{(X)}:\exists g \in A{(X)}\) such
that \({(fg)}|_{E} = 1\}\) where \(f \in {A{(X)}}\). For any ideal \(I\) in \(A{(X)}\), \(\mathcal{Z}_{A}{(I)}\) = \(\{{\mathcal{Z}_{A}{(f)}}:{f \in I}\}\)
forms a \(z\)-filter on \(X\). We refer the reader to [4], [7] and [9]
for more on this correspondence. Acharyya et al. [3], introduced a duality between special types of
ideals called \(z_{A}^{\beta}\)-ideals
in intermediate rings \(A{(X)}\) of
real-valued continuous functions and special types of \(z\)-filters on \(\beta X\) called \(z_{A}^{\beta}\)-filters.
The structure space of a commutative ring \(R\) with identity is the set \(\mathcal{M}{(R)}\) of all maximal ideals in
\(R\) equipped with the hull-kernel
topology. It is known that the structure space of \(C{(X)}\) is homeomorphic to \(\beta X\) [5]. Plank [10] and Redlin et al. [11] independently proved that the structure space of
an intermediate ring of real-valued continuous functions is homeomorphic
to the space \(\beta X\). For any
subring \(A{(X)}\) of \(C{(X)}\), let \({\lbrack{A{(X)}}\rbrack}_{c}\) = \(\{{f' +
{if^{\operatorname{\prime\prime}}}}:{{f',f^{\operatorname{\prime\prime}}}
\in {A{(X)}}}\}\). Clearly, \({\lbrack{C{(X)}}\rbrack}_{c}\) = \(C{(X,{\mathbb{C}})}\) and \({\lbrack{C^{\ast}{(X)}}\rbrack}_{c}\) =
\(C^{\ast}{(X,{\mathbb{C}})}\). If
\(A{(X)}\) \(\in\) \(\sum{(X)}\), then \({\lbrack{A{(X)}}\rbrack}_{c}\) \(\in\) \(\sum{(X,{\mathbb{C}})}\), in fact, \({\lbrack{A{(X)}}\rbrack}_{c}\) is the
smallest such ring containing \(A{(X)}\) and the constant function \(i\). Acharyya et al. [1] showed that the structure space of each \({\lbrack{A{(X)}}\rbrack}_{c}\) is
homeomorphic to \(\beta X\) .
For the ring \({\lbrack{A{(X)}}\rbrack}_{c}\), where \({A{(X)}} \in {\sum{(X)}}\), we establish a
correspondence between a special collection of ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) called \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals
and a special collection of \(z
-\)filters on \(\beta X\) called
\(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filters
in Section 2 of the paper. In Section 3, we examine the properties of
these \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals
in \({\lbrack{A{(X)}}\rbrack}_{c}\),
where \({A{(X)}} \in {\sum{(X)}}\).
Section 4 is devoted to the study of the
structure spaces of intermediate rings \({\lbrack{A{(X)}}\rbrack}_{c}\), where \({A{(X)}} \in {\sum{(X)}}\), and we show
that they are homeomorphic to \(\beta
X\). This is achieved by extending the known correspondence
between maximal ideals in \(A{(X)}\)
and \(z\)-ultrafilters on \(X\).
For each \(f\) \(\in\) \(C{(X)}\), there exists a unique continuous
extension \(f^{\ast}\) from \(\beta X\) to \({\mathbb{R}}^{\ast}\), the one-point
compactification of \(\mathbb{R}\) [5]. For any subring \(A{(X)}\) of \(C{(X)}\) and \(p\) \(\in\) \(\beta
X\), Plank [10], defined
\(M_{A}^{p}\) = \(\{ f \in A{(X)}:{(fg)}^{\ast}{(p)} = 0\)
for all \(g \in A{(X)}\}\). For \(p\) \(\in\) \(\beta
X\), \(M_{A}^{p}\) is shown to
be a prime ideal and in particular, when \(A{(X)}\) is an \(LBI\)-subalgebra of \(C{(X)}\), \(M_{A}^{p}\) is maximal in \(A{(X)}\) (\(A{(X)}\) is called closed under local
bounded inversion, briefly, \(LBI\)-subalgebra, if whenever \(f\) \(\in\) \(A{(X)}\) is bounded away from zero on some
cozero-set \(E\), then there exists
\(g\) \(\in\) \(A{(X)}\) such that \({{fg}|}_{E}\) = 1). In fact, for these
subalgebras, the collection of maximal ideals in \(A{(X)}\) is precisely \(\mathcal{M}{(A)}\) = \(\{ M_{A}^{p}:{p \in {\beta X}}\}\) [8]. For each \(f \in {A{(X)}}\) of \(C{(X)}\), Plank [10] defined the set \({S_{A}{(f)}} = {\{{p \in {\beta
X}}:{{{({fg})}^{\ast}{(p)}} = {0{\forall g}} \in {A{(X)}}}\}}\).
From the definition of \(M_{A}^{p}\),
we can clearly see that \(S_{A}{(f)}\)
= \(\{{p \in {\beta X}}:{f \in
M_{A}^{p}}\}\).
From now on, \(A{(X)}\) or \(B{(X)}\) will mean intermediate rings of
real-valued continuous functions. We set \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) =
\(\{{p \in {\beta X}}:{f \in {\lbrack
M_{A}^{p}\rbrack}_{c}}\}\). In view of [1, Theorem 2.6] and using the fact that \(M_{A}^{p}\) is absolutely convex (in fact
it is maximal), we see that \({\lbrack
M_{A}^{p}\rbrack}_{c}\) = \(\{{h \in
{\lbrack{A{(X)}}\rbrack}_{c}}:{{|h|} \in M_{A}^{p}}\}\).
Therefore, if \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\), then \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) =
\({\{{p \in {\beta X}}:{{|f|} \in
M_{A}^{p}}\}} = {S_{A}{({|f|})}}\). Since \(M_{A}^{p}\) is absolutely convex, it is
easy to see that \({S_{A}{(f)}} =
{S_{A}{({|f|})}}\) for all \(f \in
{A{(X)}}\).
For \(f\), \(g\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\), \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\)
\(\cup\) \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\) =
\(S_{A}{({|f|})}\) \(\cup\) \(S_{A}{({|g|})}\) = \(S_{A}{({{|f|}{|g|}})}\) = \(S_{A}{({|{fg}|})}\) = \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{({fg})}\).
Also, \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\)
\(\cap\) \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\) =
\(S_{A}{({|f|})}\) \(\cap\) \(S_{A}{({|g|})}\) = \(S_{A}{({{|f|}^{2} + {|g|}^{2}})}\). If we
let \(h\) = \(({{|f|}^{2} + {|g|}^{2}})\) + \(i0\), then \(h\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) and \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\)
\(\cap\) \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\) =
\(S_{A}{({|h|})}\) = \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(h)}\).
We know that the collection of all maximal ideals in \(A{(X)}\) is \(\mathcal{M}{({A{(X)}})}\) = \(\{ M_{A}^{p}:{p \in {\beta X}}\}\).
Therefore, by [1, Theorem 2.13],
the collection of all maximal ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) is \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\)
= \(\{{\lbrack M_{A}^{p}\rbrack}_{c}:{p \in
{\beta X}}\}\). Thus, we have the following Lemma.
Let \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\). Then \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\phi\) if and only if \(f\) is invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Suppose \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\phi\). Then by definition of \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\), we have \(f\) \(\notin\) \({\lbrack M_{A}^{p}\rbrack}_{c}\) for all \(p\) \(\in\) \(\beta X\). So \(f\) does not belong to any maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\). Therefore, \(f\) is invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\). Conversely, suppose \(f\) is invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\). Then for each \(p\) \(\in\) \(\beta X\), \(f\) \(\notin\) \({\lbrack M_{A}^{p}\rbrack}_{c}\). Hence, \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\phi\).
For any subset \(I\) of \({\lbrack{A{(X)}}\rbrack}_{c}\), we shall denote the set \(\{{S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}}:{f \in I}\}\) by \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I\rbrack}\) and we denote the set \(\{{S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}}:{f \in {\lbrack{A{(X)}}\rbrack}_{c}}\}\) by \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\).
Let \(\mathcal{F}\) be a non-empty subset of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\). We say that \(\mathcal{F}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\) if the following conditions hold.
\(\phi\) \(\notin\) \(\mathcal{F}\),
if \(S_{1}\) and \(S_{2}\) \(\in\) \(\mathcal{F}\), then \(S_{1}\) \(\cap\) \(S_{2}\) \(\in\) \(\mathcal{F}\),
if \(S_{1}\) \(\in\) \(\mathcal{F}\) and \(S_{2}\) \(\in\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\) such that \(S_{1}\) \(\subseteq\) \(S_{2}\), then \(S_{2}\) \(\in\) \(\mathcal{F}\).
Because of condition (c), condition (b) is equivalent to βif \(S_{1}\) and \(S_{2}\) \(\in\) \(\mathcal{F}\), then \(S_{1}\) \(\cap\) \(S_{2}\) contains a member of \(\mathcal{F}\)β.
The following statements easily follow from Lemma 2.1.
Let \(I\) be an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\). Then \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I\rbrack}\) = \(\{{S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}}:{f \in I}\}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\).
Let \(\mathcal{F}\) be a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\). Then \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta\leftarrow}{\lbrack\mathcal{F}\rbrack}\) = \(\{{f \in {\lbrack{A{(X)}}\rbrack}_{c}}:{{S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}} \in \mathcal{F}}\}\) is an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
A \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\) is said to be a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\) if it is not contained in any other \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\).
We have the following theorem which is a complex analogue of [3, Theorem 2.5].
For any \({\lbrack{A{(X)}}\rbrack}_{c}\), the following are equivalent.
Every \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter on \(\beta X\) can be extended to a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\).
Every subfamily of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\) with finite intersection property can be extended to a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\) and therefore a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\) is a subfamily of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\) which is maximal with respect to having the finite intersection property. Conversely, a subfamily \(\mathcal{F}\) of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\) having the finite intersection property and which is maximal with respect to this property is necessarily a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\).
A \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-filter \(\mathcal{F}\) on \(\beta X\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\) if and only if for any \(S\) \(\in\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack X\rbrack}\) such that \(S\) \(\cap\) \(S' \neq \phi\) for any \(S'\) \(\in\) \(\mathcal{F}\), then \(S\) \(\in\) \(\mathcal{F}\).
We already have the duality between maximal ideals in \(A{(X)}\) and \(z_{A}^{\beta}\)-ultrafilters on \(\beta X\) as given in [3, Theorem 2.6]. The analogous duality between maximal ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) and \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilters on \(\beta X\) is stated in the following theorem.
For any \({\lbrack{A{(X)}}\rbrack}_{c}\), we have
if \(M\) is a maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\), then \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack M\rbrack}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\) and
if \(\mathcal{F}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ultrafilter on \(\beta X\), then \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta\leftarrow}{\lbrack\mathcal{F}\rbrack}\) is a maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Next we state the following theorem which is a complex analogue of [3, Theorem 2.7].
Let \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\). If \(M\) is a maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\) and \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) meets every member of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack M\rbrack}\), then \(f\) \(\in\) \(M\).
For any ideal \(I\) in \({\lbrack{A{(X)}}\rbrack}_{c}\), it is easy to see that \(I\) \(\subseteq\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta\leftarrow}{\lbrack{Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I\rbrack}}\rbrack}\). An ideal \(I\) in \({\lbrack{A{(X)}}\rbrack}_{c}\) is called a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal if \(I\) = \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta\leftarrow}{\lbrack{Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I\rbrack}}\rbrack}\). There are examples of ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) which are not \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals. For instance, if we take \(I\) to be the ideal in \(C{({\mathbb{R}})}\) generated by the identity function \(\mathbf{i}:{{\mathbb{R}}\rightarrow{\mathbb{R}}}\), then the ideal \(I_{c}\) in \(\lbrack C{({\mathbb{R}}\rbrack}_{c}\) is not a \(z_{\lbrack C{({\mathbb{R}}\rbrack}_{c}}^{\beta}\)-ideal as \(S_{{\lbrack{C{({\mathbb{R}})}}\rbrack}_{c}}{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) = \(S_{C{({\mathbb{R}})}}{({|\mathbf{i}^{\mathbf{1}/\mathbf{3}}|})}\) = \(S_{C{({\mathbb{R}})}}{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) since \(\mathbf{i}^{\mathbf{1}/\mathbf{3}}\) \(\in\) \(C{({\mathbb{R}})}\). But \(S_{C{({\mathbb{R}})}}{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) = \(cl_{\beta{\mathbb{R}}}Z{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\). Also, clearly \(cl_{\beta{\mathbb{R}}}Z{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) = \(cl_{\beta{\mathbb{R}}}Z{(\mathbf{i})}\). Thus, \(S_{{\lbrack{C{({\mathbb{R}})}}\rbrack}_{c}}{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) = \(cl_{\beta{\mathbb{R}}}Z{(\mathbf{i})}\) = \(S_{C{({\mathbb{R}})}}{(\mathbf{i})}\). Therefore, \(S_{{\lbrack{C{({\mathbb{R}})}}\rbrack}_{c}}{(\mathbf{i}^{\mathbf{1}/\mathbf{3}})}\) \(\in\) \(Z_{{\lbrack{C{({\mathbb{R}})}}\rbrack}_{c}}^{\beta\leftarrow}{\lbrack{Z_{{\lbrack{C{({\mathbb{R}})}}\rbrack}_{c}}^{\beta}{\lbrack I\rbrack}}\rbrack}\), but clearly \(\mathbf{i}^{\mathbf{1}/\mathbf{3}}\) \(\notin\) \(I_{c}\).
In [3, Theorem 3.8], the authors have proved that in any \(A{(X)}\), the \(z_{A}^{\beta}\)-ideals are precisely the same as \(z\)-ideals. Also by [6, Lemma 1.0], for any commutative ring \(R\) with identity, if \(I\) is a \(z\)-ideal, then \(I\) is the intersection of the minimal prime ideals in \(R\) containing \(I\).
For any ideal \(I\) in \(A{(X)}\), we have that \(Z_{A}^{\beta}{\lbrack I\rbrack}\) \(\subseteq\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I_{c}\rbrack}\).
Let \(S_{A}{(g)}\) \(\in\) \(Z_{A}^{\beta}{\lbrack I\rbrack}\). Then \(S_{A}{(g)}\) = \(S_{A}{(h)}\) for some \(h\) \(\in\) \(I\). Since \(h\) \(\in\) \(I\) and \(I\) \(\subseteq\) \(A{(X)}\), \(h\) \(\in\) \(I_{c}\). Also, \(S_{A}{(h)}\) = \(S_{A}{({|h|})}\) = \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(h)}\) and \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(h)}\) \(\in\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I_{c}\rbrack}\). Thus, \(S_{A}{(g)}\) is also a member of \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack I_{c}\rbrack}\).
Let \(I\) be an ideal in \(A{(X)}\). Then \(I\) is a \(z_{A}^{\beta}\)-ideal in \(A{(X)}\) if and only if \(I_{c}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Suppose \(I\) is a \(z_{A}^{\beta}\)-ideal in \(A{(X)}\). Let \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) such that
\(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\)
\(\in\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack
I_{c}\rbrack}\). Then \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) =
\(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\),
for some \(g\) \(\in\) \(I_{c}\). By [1, Theorem 2.6], \(|g|\) \(\in\) \(I\). Therefore, \(S_{A}{({|f|})}\) = \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) =
\(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\) =
\(S_{A}{({|g|})}\) \(\in\) \(Z_{A}^{\beta}{\lbrack I\rbrack}\). Since
\(I\) is a \(z_{A}^{\beta}\)-ideal in \(A{(X)}\), \(|f|\) \(\in\) \(I\). From Remark 3.1, it follows that \(I\) is absolutely convex, hence by [1, Theorem 2.6], \(f\) \(\in\) \(I_{c}\), showing that \(I_{c}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal
in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Conversely, suppose \(I_{c}\) is a
\(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal
in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Let \(f\) \(\in\) \(A{(X)}\) such that \(S_{A}{(f)}\) \(\in\) \(Z_{A}^{\beta}{\lbrack I\rbrack}\). By Lemma
3.2 and using the fact that
\(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) =
\(S_{A}{({|f|})}\) = \(S_{A}{(f)}\), we have \(S_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\)
\(\in\) \(Z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}{\lbrack
I_{c}\rbrack}\). Since \(I_{c}\)
is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal
in \({\lbrack{A{(X)}}\rbrack}_{c}\), we
get \(f\) \(\in\) \(I_{c}\). Therefore, \(f\) = \(f'\) + \(if^{\operatorname{\prime\prime}}\), where
\(f'\) and \(f^{\operatorname{\prime\prime}}\) \(\in\) \(I\). But since \(f\) \(\in\) \(A{(X)}\), we must have \(f^{\operatorname{\prime\prime}}\) = 0.
Hence, \(f\) = \(f'\) \(\in\) \(I\), showing that \(I\) is a \(z_{A}^{\beta}\)-ideal in \(A{(X)}\).
Let \(I\) be an ideal in \(A{(X)}\). Then \(I_{c}\) is a \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\) if and only if given any \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\), there exists \(g\) \(\in\) \(I_{c}\) such that whenever \(f\) belongs to every maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\) containing \(g\), then \(f\) \(\in\) \(I_{c}\).
Thus the \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals in the ring \({\lbrack{A{(X)}}\rbrack}_{c}\) which are of the form \(I_{c}\) for some ideal \(I\) in \(A{(X)}\) are essentially the same as \(z\)-ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\). Consequently, since maximal and minimal prime ideals in a commutative ring are \(z\)-ideals, by [1, Remark 2.12, Theorem 2.13] we see that maximal and minimal prime ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) are \(z_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\beta}\)-ideals. Moreover, if \(I\) is a \(z_{A}^{\beta}\)-ideal in \(A{(X)}\), then together with [6, Lemma1.0], \(I_{c}\) is equal to the intersection of all the minimal prime ideals in \({\lbrack{A{(X)}}\rbrack}_{c}\) containing it.
In this section, we show that \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\) equipped with the hull-kernel topology is homeomorphic to the Stone-\(\mathcal{C}\)ech compactification \(\beta X\). As in [11], we associate each element \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) with a \(z\)-filter \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) on \(X\) and we extend this correspondence to one between \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\) and \(z\)-ultrafilters on \(X\).
For any cozero-set \(E\) in \(X\), \(f\) \(\in\) \(A{(X)}\) is said to be \(E\)-regular if there exists \(g\) \(\in\) \(A{(X)}\) such that \({{fg}|}_{E} = 1\).
Let \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\). We define \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\{ E \in Z{\lbrack X\rbrack}:|f|\) is \(E^{c}\)-regular\(\}\). It is clear that \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\mathcal{Z}_{A}{({|f|})}\).
A function \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) is invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\) if and only if \(|f|\) is invertible in \(A{(X)}\).
By [1, Theorem 2.3], we have \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) if and only if \(|f|\) \(\in\) \(A{(X)}\). Also, for any \(p\) in \(\beta X\), \(f\) \(\in\) \({\lbrack M_{A}^{p}\rbrack}_{c}\) if and only if \(|f|\) \(\in\) \(M_{A}^{p}\). Thus, the result follows from the fact that \(\mathcal{M}{({A{(X)}})}\) = \(\{ M_{A}^{p}:{p \in {\beta X}}\}\) and \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\) = \(\{{\lbrack M_{A}^{p}\rbrack}_{c}:{p \in {\beta X}}\}\).
Suppose \(f\) is not invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\), then \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) is a \(z\)-filter on \(X\) and the converse also holds.
Let \(f\) be not invertible in \({\lbrack{A{(X)}}\rbrack}_{c}\). Then
\(\phi\) \(\notin\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\). For if \(\phi\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\mathcal{Z}_{A}{({|f|})}\), then \(|f|\) would be invertible in \(A{(X)}\), which is a contradiction by Lemma 4.2.
Let \(E\), \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\). Then by [11, Lemma 1(b)], \(E \cap F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\).
Let \(E\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\) and \(F\) be a zero-set in \(X\) containing \(E\). Then, by [11, Lemma 1(a)], \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\).
Thus, \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) is a \(z\)-filter on \(X\). The converse is trivial.
Let \(I\) be a prime ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\). Then \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\) = \(\bigcup_{f \in I}{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}}\) is a \(z\)-filter on \(X\).
Since \(I\) is a prime ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\), then \(I\) = \(Q_{c}\) for some prime ideal \(Q\) in \({\lbrack{A{(X)}}\rbrack}_{c}\) \(\cap\) \(C{(X)}\) = \(A{(X)}\).
Since \(I\) is a proper ideal, clearly \(\phi\) \(\notin\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\).
Let \(E\), \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\). So, \(E\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) and \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(g)}\), for some \(f\) and \(g\) in \(I\). Then by [11, Lemma 1(e)], \({|f|}^{2} + {|g|}^{2}\) is \({({E \cap F})}^{c}\)-regular. Also, since \(I\) is absolutely convex, by [1, Theorem 2.6], we have \({|f|}^{2} + {|g|}^{2}\) \(\in\) \(Q\) \(\subseteq\) \(Q_{c}\) = \(I\). Therefore, \(E \cap F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\).
Let \(E\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\) and \(F\) be a zero-set in \(X\) containing \(E\). Then \(E\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) for some \(f\) \(\in\) \(I\). Hence, by Theorem 4.4, \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\). Thus, \(F\) \(\in\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\).
A topological description on \(\mathcal{Z}_{A}\) given by Parsinia in [9] for any \(f\) \(\in\) \(A{(X)}\) is \(\mathcal{Z}_{A}{(f)}\) = \(\{{E \in {Z{\lbrack X\rbrack}}}:{{S_{A}{(f)}} \subseteq {int_{\beta X}cl_{\beta X}E}}\}\). So, for any \(f\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\), we have \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\) = \(\mathcal{Z}_{A}{({|f|})}\) = \(\{{E \in {Z{\lbrack X\rbrack}}}:{{S_{A}{({|f|})}} \subseteq {int_{\beta X}cl_{\beta X}E}}\}\).
If \(f\), \(g\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\) be such that \(|f|\) \(\leq\) \(|g|\), then \(S_{A}{({|g|})}\) \(\subseteq\) \(S_{A}{({|f|})}\). Hence, if \(|f|\) \(\leq\) \(|g|\), then \(\mathcal{Z}_{A}{({|f|})}\) \(\subseteq\) \(\mathcal{Z}_{A}{({|g|})}\).
Let \(p\) \(\in\) \(S_{A}{({|g|})}\). Then \(|g|\) \(\in\) \(M_{A}^{p}\). Again since \(|f|\) \(\leq\) \(|g|\), \(|f|\) \(\in\) \(M_{A}^{p}\). Thus, \(p\) \(\in\) \(S_{A}{({|f|})}\) and hence \(S_{A}{({|g|})}\) \(\subseteq\) \(S_{A}{({|f|})}\). So, it follows that if \(|f|\) \(\leq\) \(|g|\), then \(\mathcal{Z}_{A}{({|f|})}\) \(\subseteq\) \(\mathcal{Z}_{A}{({|g|})}\).
For any \(z\)-filter \(\mathcal{F}\) on \(X\), \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\) = \(\{{f \in {\lbrack{A{(X)}}\rbrack}_{c}}:{{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}} \subseteq \mathcal{F}}\}\) is an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Let \(I\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\).
Let \(f\) \(\in\) \(I\) and \(g\) \(\in\) \({\lbrack{A{(X)}}\rbrack}_{c}\). Since \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{({fg})}\)
\(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}\),
we have \(fg\) \(\in\) \(I\).
If \(f\), \(g\) \(\in\) \(I\), then \(|f|\), \(|g|\) \(\in\) \(A{(X)}\) and using [11, Lemma 2], we have \(lim_{\mathcal{Z}_{A}{({|f|})}}{|f|}h\) =
\(lim_{\mathcal{Z}_{A}{({|g|})}}{|g|}h\) = 0
for every \(h\) \(\in\) \(A{(X)}\). But since \(\mathcal{Z}_{A}{({|f|})}\) \(\subseteq\) \(\mathcal{F}\) and \(\mathcal{Z}_{A}{({|g|})}\) \(\subseteq\) \(\mathcal{F}\), we have \(lim_{\mathcal{F}}{|f|}h\) = \(lim_{\mathcal{F}}{|g|}h\) = 0 for every
\(h\) \(\in\) \(A{(X)}\). Therefore, \(lim_{\mathcal{F}}{|f|}h\) + \(lim_{\mathcal{F}}{|g|}h\) = \(lim_{\mathcal{F}}{({{|f|} + {|g|}})}h\) = 0
for every \(h\) \(\in\) \(A{(X)}\). Thus, by [11, Lemma 3], \(\mathcal{Z}_{A}{({{|f|} + {|g|}})}\) \(\subseteq\) \(\mathcal{F}\). Again, since \(|{f + g}|\) \(\leq\) \({|f|} +
{|g|}\), by Lemma 4.8 we have \(\mathcal{Z}_{A}{({|{f + g}|})}\) \(\subseteq\) \(\mathcal{Z}_{A}{({{|f|} + {|g|}})}\) and
hence \(f + g\) \(\in\) \(I\). It is easy to see that \(I\) contains no invertible element of \({\lbrack{A{(X)}}\rbrack}_{c}\). Therefore,
\(I\) is an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
Let \(I\) be an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\) and \(\mathcal{F}\) be a \(z\)-filter on \(X\). Then
\(I\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}}\rbrack}\) and the equality holds when \(I\) is maximal,
\(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}}\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\),
\(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}}\rbrack}\) \(\subseteq\) \(\mathcal{F}\),
\(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}}\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\).
The proof clearly follows from the definition of \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}\) and \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}\).
Let \(B{(X)}\) \(\subseteq\) \(A{(X)}\). Then for any absolutely convex ideal \(I\) of \({\lbrack{A{(X)}}\rbrack}_{c}\), \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}\) = \(\mathcal{Z}_{{\lbrack{B{(X)}}\rbrack}_{c}}{\lbrack{I \cap {\lbrack{B{(X)}}\rbrack}_{c}}\rbrack}\).
It is sufficient to show that \({\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}} \subseteq {\mathcal{Z}_{{\lbrack{C^{\ast}{(X)}}\rbrack}_{c}}{\lbrack{I \cap {\lbrack{C^{\ast}{(X)}}\rbrack}_{c}}\rbrack}}\). Let \(E \in {\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack I\rbrack}}\). Then there exists \(f \in I\) and \(g \in {\lbrack{A{(X)}}\rbrack}_{c}\) such that \({(|f|.g)}|_{({X\backslash E})} = 1\). Let \(h = \frac{{2{|f|}}.g}{1 + |f.g|}\). Then \(h \in {I \cap {\lbrack{C^{\ast}{(X)}}\rbrack}_{c}}\) and \({h|}_{({X\backslash E})} = 1\). This shows that \(E \in {\mathcal{Z}_{{\lbrack{C^{\ast}{(X)}}\rbrack}_{c}}{\lbrack{I \cap {\lbrack{C^{\ast}{(X)}}\rbrack}_{c}}\rbrack}}\).
For any maximal ideal \(M\) in \(A{(X)}\), \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack M\rbrack}\) is contained in a unique \(z\)-ultrafilter on \(X\).
Given that \(M\) is a maximal ideal in \(A{(X)}\). Let \(\mathcal{F}\) be a \(z\)-ultrafilter on \(X\) containing \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}\). Since the mapping \(Z\) defined by \(Z{\lbrack I\rbrack}\) = \(\{{Z{(f)}}:{f \in I}\}\), where \(I\) is an ideal in \(C{(X)}\), is a bijection from the set of
all maximal ideals in \(C{(X)}\) and
\(z\)-ultrafilters on \(X\), there is a maximal ideal \(J\) in \(C{(X)}\) with \(\mathcal{F}\) = \(Z{\lbrack J\rbrack}\). So, we get \(M\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack
J\rbrack}}\rbrack}\). Since \(M\) is maximal so \(M\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack
J\rbrack}}\rbrack}\). Also, \(J \cap
{\lbrack{A{(X)}}\rbrack}_{c}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{J
\cap {\lbrack{A{(X)}}\rbrack}_{c}}\rbrack}}\rbrack}\) and by
Lemma 4.14, we have
\(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{J
\cap {\lbrack{A{(X)}}\rbrack}_{c}}\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack
J\rbrack}}\rbrack}\). Again, \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack
J\rbrack}}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack
J\rbrack}}\rbrack}\) = \(M\).
Thus, \(\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack
J\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}\) \(\subseteq\) \(Z{\lbrack J\rbrack}\).
If there exists another \(z\)-ultrafilter \(Z{\lbrack J^{'}\rbrack}\), where \(J^{'}\) is a maximal ideal in \(C{(X)}\), with \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}\) \(\subseteq\) \(Z{\lbrack J^{'}\rbrack}\), then
similarly as above we get \(\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack
J^{'}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}\) \(\subseteq\) \(Z{\lbrack J^{'}\rbrack}\). So, it
follows that any zero-set \(F\) in
\(Z{\lbrack J^{'}\rbrack}\)
intersects every member of \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack
M\rbrack}\) and thus \(F\)
intersects with every member of \(\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack
J\rbrack}\). Therefore, \(F\)
intersects with every member of \(Z{\lbrack
J^{'}\rbrack}\) giving that \(F\) \(\in\) \(Z{\lbrack
J\rbrack}\). Hence, \(Z{\lbrack
J\rbrack}\) = \(Z{\lbrack
J^{'}\rbrack}\).
Let \(\mathcal{F}\) be a \(z\)-ultrafilter on \(X\). Then \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\) is a maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\).
By Theorem 4.10, \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\) is an ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\). Since \(\mathcal{F}\) is a \(z\)-ultrafilter, so \(\mathcal{F}\) = \(Z{\lbrack J\rbrack}\) for some maximal ideal \(J\) in \(C{(X)}\). Now, \(J \cap {\lbrack{A{(X)}}\rbrack}_{c}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{J \cap {\lbrack{A{(X)}}\rbrack}_{c}}\rbrack}}\rbrack}\) and by Lemma 4.14, we have \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{J \cap {\lbrack{A{(X)}}\rbrack}_{c}}\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack J\rbrack}}\rbrack}\). Again, \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack J\rbrack}}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack J\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\). If \(J^{'}\) is a maximal ideal in \({\lbrack{A{(X)}}\rbrack}_{c}\) with \(J\) \(\cap\) \({\lbrack{A{(X)}}\rbrack}_{c}\) \(\subseteq\) \(J^{'}\), then \(\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack J\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack{J \cap {\lbrack{A{(X)}}\rbrack}_{c}}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack J^{'}\rbrack}\). If we take \(J^{^{\operatorname{\prime\prime}}}\) to be a maximal ideal in \(C{(X)}\) such that \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack J^{'}\rbrack}\) \(\subseteq\) \(Z{\lbrack J^{^{\operatorname{\prime\prime}}}\rbrack}\), then by same argument as above, we get \(\mathcal{Z}_{{\lbrack{C{(X)}}\rbrack}_{c}}{\lbrack J^{^{\operatorname{\prime\prime}}}\rbrack}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack J^{'}\rbrack}\) and \(Z{\lbrack J^{^{\operatorname{\prime\prime}}}\rbrack}\) = \(Z{\lbrack J\rbrack}\). Hence, \(J^{'}\) \(\subseteq\) \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack J\rbrack}}\rbrack}\). But \(J^{'}\) is maximal, therefore \(J^{'}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{Z{\lbrack J\rbrack}}\rbrack}\) = \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{F}\rbrack}\).
For each \(A{(X)}\), the structure space of \({\lbrack{A{(X)}}\rbrack}_{c}\) is homeomorphic to \(\beta X\).
Let \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\) be the structure space of \({\lbrack{A{(X)}}\rbrack}_{c}\). Since for each \(M \in {\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}}\), \(\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack M\rbrack}\) is contained in a unique \(z\)-ultrafilter \(\mathcal{U}_{M}\) on \(X\), this defines a map \(\psi:{{\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}}\rightarrow{\beta X}}\) given by \({\psi{(M)}} = \mathcal{U}_{M}\) and note that \({\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{U}_{M}\rbrack}} \supseteq {\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{\lbrack M\rbrack}}\rbrack}} = M\) (because of the maximality of \(M\) in \({\lbrack{A{(X)}}\rbrack}_{c}\)) implies that \({\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}^{\leftarrow}{\lbrack\mathcal{U}_{M}\rbrack}} = M\). Thus, \(\psi\) is a bijection onto \(\beta X\). For any \(f \in {\lbrack{A{(X)}}\rbrack}_{c}\), \({\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}} \subseteq \mathcal{U}_{M}\) if and only \(f \in M\). Now, a typical basic closed set in \(\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}\) is \({\mathcal{M}{(f)}} = {\{{M \in {\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}}}:{f \in M}\}}\) and therefore, \({\psi{({\mathcal{M}{(f)}})}} = {\{\mathcal{U}_{M{(f)}}:{{\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}} \subseteq \mathcal{U}_{M{(f)}}}\}} = {\bigcap\limits_{Z \in {\mathcal{Z}_{{\lbrack{A{(X)}}\rbrack}_{c}}{(f)}}}{\{{\mathcal{U} \in {\beta X}}:{Z \in \mathcal{U}}\}}}\), a basic closed set in \(\beta X\). Thus, \(\psi:{{\mathcal{M}{({\lbrack{A{(X)}}\rbrack}_{c})}}\rightarrow{\beta X}}\) becomes a closed bijection on the domain space onto the range space. Since both the domain and range spaces are compact Hausdorff space, \(\psi\) turns out to be a homeomorphism.